![Lecture 35 : Prime ideals in Polynomial rings video lecture by Prof Prof. Dilip P. Patil of IIT Bombay Lecture 35 : Prime ideals in Polynomial rings video lecture by Prof Prof. Dilip P. Patil of IIT Bombay](https://i.ytimg.com/vi/0Ei2ztFJklA/hqdefault.jpg)
Lecture 35 : Prime ideals in Polynomial rings video lecture by Prof Prof. Dilip P. Patil of IIT Bombay
![abstract algebra - How do we show that an ideal of polynomials is prime - Mathematics Stack Exchange abstract algebra - How do we show that an ideal of polynomials is prime - Mathematics Stack Exchange](https://i.stack.imgur.com/MwD4P.png)
abstract algebra - How do we show that an ideal of polynomials is prime - Mathematics Stack Exchange
![SOLVED: (PRIME IDEALS IN Z[X]) Consider the ring Z[X]. Consider the map φ: Z[X] â†' Z given by φ(f) = f(0), which is obviously a ring homomorphism. Show that ker φ = ( SOLVED: (PRIME IDEALS IN Z[X]) Consider the ring Z[X]. Consider the map φ: Z[X] â†' Z given by φ(f) = f(0), which is obviously a ring homomorphism. Show that ker φ = (](https://cdn.numerade.com/ask_images/b039fdff90814846b1e77d3ea4b91a5b.jpg)
SOLVED: (PRIME IDEALS IN Z[X]) Consider the ring Z[X]. Consider the map φ: Z[X] â†' Z given by φ(f) = f(0), which is obviously a ring homomorphism. Show that ker φ = (
![Modern Algebra || Ring Theory || Lecture-30 || Ideals in Polynomial ring of two Variables R[x,y] - YouTube Modern Algebra || Ring Theory || Lecture-30 || Ideals in Polynomial ring of two Variables R[x,y] - YouTube](https://i.ytimg.com/vi/Z6Y1keiDC9E/hqdefault.jpg?v=60c25dce)
Modern Algebra || Ring Theory || Lecture-30 || Ideals in Polynomial ring of two Variables R[x,y] - YouTube
![SOLVED: Text: Abstract Algebra Suppose that R is a ring and I is an ideal of R. 1. Verify that the function f: R -> R/I defined by f(r) = r + SOLVED: Text: Abstract Algebra Suppose that R is a ring and I is an ideal of R. 1. Verify that the function f: R -> R/I defined by f(r) = r +](https://cdn.numerade.com/ask_images/ab5f49a3c0df4c1b977348e7f8e4692c.jpg)